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Elementary Statistics Homework  1  2  3  4  5-6  6.3-7   8-10   |  Tests Chapter  1-3   4   5-6  6.3-7  8-10    Final Review
Elementary Statistics (STA2023)
Homework 8 - 10


8.1.0
 
Most adults would not......mean less than 50 % do not erase all of their personal information.
 
Claim: Most adults would not erase all of their personal information online if they could. A software firm survey of 466
randomly selected adults showed that 44% of them would erase all of their personal information online if they could.
Complete parts​ (a) and​ (b) below.
Express the original claim in symbolic form. Let the parameter represent the adults that would erase their personal information.
 
P < 0.50
Type an integer or a decimal. Do not round.)
 
H0: P = 0.50
H1: P < 0.50
 
The claim involves a population proportion.
 
8.1.17
 
The test statistic of z = 0.99 is obtained when testing the claim that p > 0.8
Identify the hypothesis test as being​ two-tailed, left-tailed, or​ right-tailed.
Find the​ P-value.
Using a significance level of a = 0.10​ should we reject Upper H0   or should we fail to reject Upper H0 ​?
 
This is a right-tailed test.
 a = 0.05
 
If ​P-value ≤ a reject a
If ​P-value > than a fail to reject
 
This is a right-tailed test
 
P-value = 0.176
a = .01
Fail to reject H0 There is not sufficient evidence to support the claim that p > 0.8
 
P-value = 0.008
a = .05
Reject H0. There is sufficient evidence to support the claim that p > 0.5
 
P-value = 0.161
a = .01
 
Fail to reject H0 There is not sufficient evidence to support the claim that p > 0.4
Reject H0. There is not sufficient evidence to support the claim that p > 0.9
Reject H0. There is sufficient evidence to support the claim that p > 0.9
Fail to reject H0 There is not sufficient evidence to support the claim that p > 0.9
Fail to reject H0. There is sufficient evidence to support the claim that p > 0.9.
 

 
8.1.19
 
The test statistic of z = 2.43 is obtained when testing the claim that p ≠ 0.675.
a. Identify the hypothesis test as being​ two-tailed, left-tailed, or​ right-tailed.
b. Find the​ P-value. c. Using a significance level of a = 0.05​, should we reject Upper H0   or should we fail to reject Upper H0 ​?

 
This is a two-tailed test
 
Since the alternative hypothesis is H 1 ​:  p ≠ 0.474​, this is a two ​-tailed test.
 
a = 0.05
 
If ​P-value ≤ “a” reject H0, If ​P-value > than “a” fail to reject H0
 
P-value = 0.015 ​
A = .05
Reject H0. There is sufficient evidence to support the claim that ≠ 0.675
 
P-value = 0.121
A = .10
Fail to Reject H0. There is not sufficient evidence to support the claim that ≠ 0.182
 
P-value = 0.026
A = .01
 
Fail to Reject H0. There is not sufficient evidence to support the claim that ≠ 0.209
Fail to Reject H0. There is not sufficient evidence to support the claim that ≠ 0.838
Reject H0. There is sufficient evidence to support the claim that ≠ 0.149
 

 
8.1.22
 
The test statistic of z = -2.38 is obtained when testing the claim that p < 0.37 a. Using a significance level of a = 0.05
find the critical​ value(s). b. Should we reject H0   or should we fail to reject Upper H0 ​?

 
If test statistic is in the critical​ region, reject H0
If test statistic is not in the critical​ region, fail to reject H0
 
test statistic of z = -2.38, a = .05 p < .37
The critical value(s) is/are = -1.65
a = .05
Reject H0. There is sufficient evidence to support the claim that p < 0.37
 
The test statistic of z = -2.38, a = .05 p < 27
The critical value(s) is/are = -1.65
Reject H0. There is sufficient evidence to support the claim that p < 0.37
 
The test statistic of z = -1.63, a = .01 p < 45
The critical value(s) is/are = -2.33
 
Fail to reject   H0.  There is not sufficient evidence to support the claim that p < 0.45


8.1.24
 
The test statistic of z = -2.68 is obtained when testing the claim that p = 2/3.
Using a significance level of a = 0.10 ​, find the critical​ value(s).
Should we reject Upper H0   or should we fail to reject Upper H0 ​?
 
The critical​ value(s) is/are z = -1.65, 1.65
​(Round to two decimal places as needed. Use a comma to separate answers as​ needed.)
 
https://statscalculator.com/zcriticalvaluecalculator

Enter 0.10
 
Choose the correct conclusion below.
 
If test statistic is in the critical​ region, reject H0
If test statistic is not in the critical​ region, fail to reject H0
 
Reject Upper H0 There is sufficient evidence to warrant rejection of the claim that p = 2/3
Fail to reject H0 There is sufficient evidence to warrant rejection of the claim that p = 2/3
Fail to reject H0 There is not sufficient evidence to warrant rejection of the claim that p = 2/3
Reject H0 There is not sufficient evidence to warrant rejection of the claim that p = 2/3.
 
Reject Upper H0 There is sufficient evidence to warrant rejection of the claim that p = 2/3
Fail to reject H0 There is sufficient evidence to warrant rejection of the claim that p = 2/3
Fail to reject H0 There is not sufficient evidence to warrant rejection of the claim that p = 2/3
Reject H0 There is not sufficient evidence to warrant rejection of the claim that p = 2/3.
 
Assume a significance level of alpha equals 0.05 and use the given information to complete parts​ (a) and​ (b) below.
Original​ claim: Less than 53​% of adults would erase all of their personal information online if they could.
The hypothesis test results in a​ P-value of 0.2916
 
Fail to reject H0 because the​ P-value is greater than a
 
Without using technical​ terms, state a final conclusion that addresses the original claim.
Which of the following is the correct​ conclusion?

 
There is not sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online, if they could is less than 53 ​%.

 
Assume a significance level of alpha equals 0.05 and use the given information to complete parts​ (a) and​ (b) below.
Original​ claim: Less than 56​% of adults would erase all of their personal information online if they could. The hypothesis test results in a​ P-value of 0.1517
 
Fail to reject H0 because the​ P-value is greater than a
 
Without using technical​ terms, state a final conclusion that addresses the original claim.
Which of the following is the correct​ conclusion?

 
There is not sufficient evidence to support the claim that the percentage of adults that would erase all of
their personal information online,
if they could is less than 56%.
 
A. Fail to reject H0 because the​ P-value is less than or equal to a
B. Fail to reject H0 because the​ P-value is greater than a
C. Reject H0 because the​ P-value is less than or equal to a
D. Reject H0 because the​ P-value is greater than a
 
A. There is sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information
online if they could is less than 53%.

B. The percentage of adults that would erase all of their personal information online if they could is more than or equal to 53 ​%.
C. The percentage of adults that would erase all of their personal information online if they could is less than 53 ​%.
D. There is not sufficient evidence to support the claim that the percentage of adults that would erase all of their personal information online if they could is less than 53 %.
 

 
Assume a significance level of a = 0.01 and use the given information to complete parts​ (a) and​ (b) below.
Original​ claim: The mean pulse rate​ (in beats per​ minute) of a certain group of adult males is 73 bpm.
The hypothesis test results in a​ P-value of 0.0709. a. State a conclusion about the null hypothesis.​
(Reject Upper H 0 or fail to reject Upper H 0 ​.)  Choose the correct answer below.

 
D. Fail to reject H0 because the P-value is greater than a
 
Without using technical​ terms, state a final conclusion that addresses the original claim. Which of the following is the correct​ conclusion?
 
C. There is not sufficient evidence to warrant rejection of the claim that the mean pulse rate​ (in beats per​ minute) of the group of adult males is 73   bpm.
 

 
Assume a significance level of a = 0.01 and use the given information to complete parts​ (a) and​ (b) below. 
Original​ claim: The mean pulse rate​ (in beats per​ minute) of a certain group of adult males is 70 bpm.
The hypothesis test results in a​ P-value of 0.0659. a. State a conclusion about the null hypothesis.​
(Reject Upper H 0 or fail to reject Upper H 0 ​.)
Choose the correct answer below.
 
Fail to reject H0 because the P-value is greater than a
 
Without using technical​ terms, state a final conclusion that addresses the original claim.
Which of the following is the correct​ conclusion?
 
There is not sufficient evidence to warrant rejection of the claim that the mean pulse rate​
(in beats per​ minute) of the group of adult males is 70 bpm.
 
A. Reject H0 because the P-value is greater than a
B. Fail to reject H0 because the P-value is less than or equal to a
C. Reject H0 because the P-value is less than or equal to a
D. Fail to reject H0 because the P-value is greater than a
 
A. There is sufficient evidence to warrant rejection of the claim that the mean pulse rate​ (in beats per​ minute)
of the group of adult males is 73   bpm.
B. The mean pulse rate​ (in beats per​ minute) of the group of adult males is 73   bpm.
C. There is not sufficient evidence to warrant rejection of the claim that the mean pulse rate​ (in beats per​ minute)
of the group of adult males is 73   bpm.
D. The mean pulse rate​ (in beats per​ minute) of the group of adult males is not 73   bpm
 


A certain drug is used to treat asthma. In a clinical trial of the​ drug, 27 of 257 treated subjects experienced headaches​
(based on data from the​ manufacturer). The accompanying calculator display shows results from a test of the claim that
less than 9​% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial
distribution and assume a 0.05 significance level to complete parts​ (a) through​ (e) below.
 
a. Is the test​ two-tailed, left-tailed, or​ right-tailed? ​
Left-tailed test
 
What is the test​ statistic? z = 0.84
​(Round to two decimal places as​ needed.)
 
What is the​ P-value?
P-value = 0.8005

p = p-value
 

TI84 Plus Instructions:
STAT     TESTS     PropZTest
P0: 0.09
x: 27
n: 257
Calculate, Then Enter
 
z = 0.843533729
p = 0.8005349949
p(hat) = 0.1050583658
n = 257
 
Decide whether to reject the null hypothesis. Choose the correct answer below.
Fail to reject   the null hypothesis because the​ P-value is > the significance​ level, a
 
What is the final​ conclusion?
There is not sufficient evidence to support the claim that less than 9% of treated subjects experienced headaches.
 
Consider the significance​ level, α​, and the​ P-value to decide if the null​ hypothesis, H0​, should be rejected.
If the​ P-value is less than or equal to the significance​ level, reject the null hypothesis.
If the​ P-value is greater than the significance​ level, fail to reject the null hypothesis.
 

 
8.2.10T
Consider a drug that is used to help prevent blood clots in certain patients. In clinical​ trials, among 6187 patients
treated with this​ drug, 161   developed the adverse reaction of nausea. Use a 0.05   significance level to test the
claim that 3​% of users develop nausea. Does nausea appear to be a problematic adverse​ reaction?
 
Identify the null and alternative hypotheses for this test. Choose the correct answer below.
 
H0: p = .03
H0: p ≠ .03

Identify the test statistic for this hypothesis test.
The test statistic for this hypothesis test is -1.83
​(Round to two decimal places as​ needed.)
 
TI84 Plus Instructions:
STAT / TEST / stats
PropZTest: P:  .03 / x: 161 / n: 6167 / ≠p
 
The​ P-value for this hypothesis test is 0.067
(Round to three decimal places as​ needed.)
 
TI84 Plus Instructions:
2nd    VARS      Normalcdf
-9999
-1.83
0
1
= .0336249107


0.0336249107 x 2 = 0.0672498214
 
Identify the conclusion for this hypothesis test.
 
A. Fail to reject   Upper H0 .  There is   sufficient evidence to warrant rejection of the claim that 3 ​% of users develop nausea.
B. Reject   Upper H 0.  There is  sufficient evidence to warrant rejection of the claim that 3 % of users develop nausea.
C. Fail to reject   Upper H0 .  There is not   sufficient evidence to warrant rejection of the claim that 3 ​% of users develop nausea. Your answer is correct.
D. Reject   Upper H0 .  There is not   sufficient evidence to warrant rejection of the claim that 3 ​%  of users develop nausea.
 
Does nausea appear to be a problematic adverse​ reaction?
Since the rate of nausea appears to be relatively low, it is not a problematic adverse reaction.
 

 
Suppose that in a random selection of 100 colored​ candies, 21% of them are blue. The candy company claims that the percentage of blue candies is equal to 26%. Use a 0.01   significance level to test that claim.
 
Identify the null and alternative hypotheses for this test. Choose the correct answer below.
 
H0​: p = 0.26
H0​: p ≠0.26
 
Null hypothesis: H0: p = 0.26
Alternative hypothesis: H0: 0≠ 0.26
 
Identify the test statistic for this hypothesis test.
The test statistic for this hypothesis test is -1.14
​(Round to two decimal places as​ needed.)
 
TI84 Plus Instructions:
STAT      TESTS
      PropZTest
P: = 0.26
x = 21
n = 100
≠p

z = -1.139901891
 
Identify the​ P-value for this hypothesis test.

The​ P-value for this hypothesis test is 0.254   (Round to three decimal places as​ needed.)
 
TI84 Plus Instructions:
2nd     VARS     Normalcdf:
-9999
-1.14
0
1
= 0.12714132013 x 2


0.12714132013 x 2 = 0.2542

https://www.graphpad.com/quickcalcs/pvalue1.cfm
 
Identify the conclusion for this hypothesis test.
 
A. Fail to reject Upper H0.
There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 26 %
B. Reject Upper H0. There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 26​%
C. Reject Upper H0. There is sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 26%
D. Fail to reject Upper H0. There is sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 26 %


Elementary Statistics Homework  1  2  3  4  5-6  6.3-7   8-10   |  Tests Chapter  1-3   4   5-6  6.3-7  8-10    Final Review


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