Accounting | Business | Computer Science | General Studies | Math | Sciences | Civics Exam | Help/Support | Join/Cancel | Contact Us | Login/Log Out Elementary Statistics Homework 1 2 3 4
5-6 6.3-7
8-10 | Tests Chapter 1-3
4 5-6 6.3-7 8-10 Final Review
Elementary Statistics
(STA2023)
Chapter Test 8 - 10 A data set includes data from 400 random
tornadoes.
The display from technology available below results from using the tornado lengths (miles) to test the claim that the mean tornado length is greater than 2.1 miles. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. ![]() H0: μ = 2.1 H1: μ > 2.1 Explanation: This is given above! Identify the test statistic. 2.35 (Round to two decimal places as needed.) This is given above: T-Stat 2.353835 (round to two decimal places) Identify the P-value. .010 (Round to three decimal places as needed.) This is given above: P-value 0.0095 (round to three decimal places) Reject HO. There is sufficient evidence to support the claim that the mean tornado length is greater than 2.1 miles.
In a study of 785 randomly selected medical
malpractice lawsuits, it was found that 512 of them were dropped or dismissed.
Use a 0.01 significance level to test the claim that most medical malpractice lawsuits are dropped or dismissed. Part 1 H0: p = 0.50 H1: p ≠ 0.50 Part 2 What is the test statistic? 8.53 (Round to three decimal places as needed.) Part 3 What is the conclusion about the null hypothesis? Reject the null hypothesis because the P-value is greater than the significance level, a. Explanation: Part 1 H0: p = 0.50 H1: p ≠ 0.50 We are looking for this test statistic. USE THE TI84 PLUS STAT TESTS PropZTest: P: = .50 | x = 512 | n = 785 | ≠p (make sure ≠p is highlighted) | Calculate z = 8.530275792 (round to 8.53) *Note the PropZTest is 5:1 PropZTest. Part 2 TI84 PLUS 2nd | VARS Normalcdf: -9999 / -8.53 / 0 / 1 = 0 Or TI84 PLUS 2nd | VARS Normalcdf: -9999 / 8.53 / 0 / 1 = 1 P (z > 8.53) = 1 – P (z < 8.53) = 0 Part 3 Reject the null hypothesis because the P-value is greater than the significance level, a. We would reject the null hypothesis since the P-Value of 0 is less than the 0.01 significance level. randomly selected adults showed that 41% of them would erase all of their personal information online if they could. Complete parts (a) and (b) below. a. Express the original claim in symbolic form. Let the parameter represent the adults that would erase their personal information. P < 0.50 Type an integer or a decimal. Do not round.) b. Identify the null and alternative hypothesis. H0: P = 0.50 H1: P < 0.50 Which of the following statements about correlation is true? Choose the correct answer below. A. We say that there is a positive correlation between x and y if the x-values increase as the corresponding y-values increase. B. We say that there is a negative correlation between x and y if the x-values increase as the corresponding y-values increase. C. We say that there is a positive correlation between x and y if there is no distinct pattern in the scatterplot_ D. We say that there is a positive correlation between x and y if the x-values increase as the corresponding y-values decrease. The table provided below shows paired data for the heights of a certain country’s presidents, and their main opponents in the election campaign. Construct a scatterplot. Does there appear to be a correlation? ![]() Choose the correct scatterplot below. ![]() Does there appear to be a correlation between the president's height and his opponent's height? A. Yes, there appears to be a correlation. The candidate with the highest height usually wins. B. Yes, there appears to be a correlation. As the president's height increases, his opponent's height decreases. C. Yes, there appears to be a correlation. As the president's height increases, his opponent's height increases. D. No, there does not appear to be a correlation because there is no general pattern to the data.
Assume a significance level of a = 0.01 and
use the given information to complete parts (a) and (b) below.
Original claim: The mean pulse rate (in beats per minute) of a certain group of adult males is 71 bpm. The hypothesis test results in a P-value of 0.0035. a. State a conclusion about the null hypothesis. (Reject Upper H 0 or fail to reject Upper H 0 .) Choose the correct answer below. A. Reject Ho because the P-value is less than or equal to a. B. Reject Ho because the P-value is greater than a. C. Fail to reject Ho because the P-value is greater than a. D. Fail to reject H0 because the P-value is less than or equal to a. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? A. There is sufficient evidence to warrant rejection of the claim that the mean pulse rate (in beats per minute) of the group of adult males is 71 bpm. B. The mean pulse rate (in beats per minute) of the group of adult males is not 71 bpm. C. The mean pulse rate (in beats per minute) of the group of adult males is 71 bpm. D. There is not sufficient evidence to warrant rejection of the claim that the mean pulse rate (in beats per minute) of the group of adult males is 71 bpm. A certain drug is used to treat asthma. In a clinical trial of the drug, 27 of 257 treated subjects experienced headaches (based on data from the manufacturer). The accompanying calculator display shows results from a test of the claim that less than 9% of treated subjects experienced headaches. Use the normal distribution as an approximation to the binomial distribution and assume a 0.05 significance level to complete parts (a) through (e) below. a. Is the test two-tailed, left-tailed, or right-tailed? Left-tailed test b. What is the test statistic? z = 0.84 (Round to two decimal places as needed.) c. What is the P-value? P-value = 0.8005 TI84 Plus STAT | TESTS | PropZTest P0: 0.09 x: 27 n: 257 Calculate Then Enter z = 0.843533729 p = 0.8005349949 p(hat) = 0.1050583658 n = 257 Using the pair of values for all 10 points, find the equation of the regression line. After removing the point with coordinates left parenthesis (1, 2) use the pairs of values for the remaining 9 points and find the equation of the regression line. ![]() 3 4 5 3 4 5 3 4 5 1 7 7 7 6 6 6 5 5 5 2 What is the equation of the regression line for all 10 points. Ŷ = 2.766 + .766 STAT / Enter X,Y data / STAT / CALC / 8:LinReg (make sure xList is L1, yList L2) A = 2.765957447 B = .7659574468 What is the equation of the regression line for the set of 9 points? Ŷ = 6 (Round to three decimal places as needed.) http://www.alcula.com/calculators/statistics/scatter-plot/ Linear regression Remove 1,2 from list 1 and list 2 STAT / Enter X,Y data / STAT / CALC / 8:LinReg 6(a) – 0(b) = 6 A data set about speed dating includes "like" ratings of male dates made by the female dates. The summary statistics are n = 189, x = 7.84, s = 1.95. Use a 0.05 significance level to test the claim that the population mean of such ratings is less than 8.00. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. HO: µ = 8.0 HO: µ < 8.0 Determine the test statistic. -1.13 (Round to two decimal places as needed.) TI84 Plus STAT | TESTS | Stats| 1:Z-Test M: 8 / o: 1.95 / X: 7.84 / N 189 / <m or (8 – 7.84) / 1.95 √189 Determine the P-value. 0.130 (Round to three decimal places as needed.) TI84 Plus 2nd | VARS tcdf lower: -9999 upper: -1.13 df: 188 enter, enter. .129957… (round to 0.130) State the final conclusion that addresses the original claim. Fail to reject H0. There is not sufficient evidence to conclude that the mean of the population of ratings is less than 8.00. Explanation: If P-value ≤ α reject H0 If P-value > α fail to reject H0 Sixteen different video games showing drug use drug use were observed. The duration times of drug use (in seconds) were recorded. When using this sample for a t-test of the claim that the population mean is greater than 9292 sec, what does df denote, and what is its value? What does df denote? A. The sample standard deviation. B. The test statistic. C. The number of degrees of freedom. D. The sample size. The value of df is 15. (Type an integer or a decimal. Do not round.) Sixteen (16 – 1) = 15 Fill in the blank. In working with two variables related by a regression equation, the _______ in a variable is the amount that it changes when the other variable changes by exactly one unit. marginal change The test statistic of z = 0.99 is obtained when testing the claim that p > 0.8 Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. Find the P-value. Using a significance level of a = 0.10 should we reject Upper H0 or should we fail to reject Upper H0? This is a right-tailed test. P Value = 0.161 Normalcdf: -9999 | .99 | 0 | 1 = 0.8389129 (round to 4 decimals) 1 - .8389 = 0.161 Choose the correct conclusion below. A. Fail to reject Upper H0. There is sufficient evidence to support the claim that p > 0.8. B. Reject Upper H0. There is sufficient evidence to support the claim that p > 0.8. C. Fail to reject Upper H0. There is not sufficient evidence to support the claim that p > 0.8. D. Reject Upper H0. There is not sufficient evidence to support the claim that p > 0.8. Claim: The mean pulse rate (in beats per minute) of adult males is equal to 68.6 bpm. For a random sample of 128 adult males, the mean pulse rate is 68.4 bpm and the standard deviation is 11.3 bpm. Complete parts (a) and (b) below. a. Express the original claim in symbolic form. µ = 68.6 (Type an integer or a decimal. Do not round.) b. Identify the null and alternative hypotheses. H0: µ = 68.6 H1: P ≠ 68.6 Suppose that in a random selection of 100 colored candies, 21% of them are blue. The candy company claims that the percentage of blue candies is equal to 26%. Use a 0.01 significance level to test that claim. Identify the null and alternative hypotheses for this test. Choose the correct answer below. H0: p = 0.26 H0: p ≠ 0.26 Null hypothesis: H0: p = 0.26 Alternative hypothesis: H0: 0≠ 0.26 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is -1.14 (Round to two decimal places as needed.) TI84 Plus STAT | TESTS PropZTest: P: = .26 | x = 21 | n = 100 | ≠p Z = -1.139901891 Identify the P-value for this hypothesis test. The P-value for this hypothesis test is 0.254 (Round to three decimal places as needed.) TI84 Plus 2nd | VARS Normalcdf: -9999 | -1.14 | 0 | 1 = .12714132013 x 2 .12714132013 x 2 = .2542 https://www.graphpad.com/quickcalcs/pvalue1.cfm Identify the conclusion for this hypothesis test. A. Fail to reject Upper H0. There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 26 % B. Reject Upper H0. There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 26% . C. Reject Upper H0. There is sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 26%. D. Fail to reject Upper H0. There is sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 26%. Different hotels in a certain area are randomly selected, and their ratings and prices were obtained online. Using technology, with x representing the ratings and y representing price, we find that the regression equation has a slope of 140 and a ŷ of -388 Complete parts (a) and (b) below. a. What is the equation of the regression line? Select the correct choice below and fill in the answer boxes to complete your choice. ŷ = -388 + (140)x Explanation: The values are given as the slope: 140 and a ŷ of -388 b. What does the symbol Modifying Above y with caret represent? A. The symbol ŷ represents the average price of hotels in the area. B. The symbol ŷ with represents the expected price when the hotel's rating is 0. C. The symbol ŷ represents the predicted value of price. D. The symbol ŷ with represents the amount that price increases with a 1-point increase in rating. The __________ is a value used in making a decision about the null hypothesis and is found by converting the sample statistic to a score with the assumption that the null hypothesis is true. test statistic In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6955 subjects randomly selected from an online group involved with ears. There were 1284 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. H0: p = 0.20 H1: p < 0.20 What is the test statistic z = -3.21 (Round to two decimal places as needed.) P = .20 | X = 1284 | N = 6955 STAT | TESTS | PropZTest: P: = .20 | x =1284 | n = 6955 | P | = -3.207563178 P-value = 0.001 (Round to three decimal places as needed.) https://www.graphpad.com/quickcalcs/pvalue1.cfm TI84 Plus 2nd VARS Normalcdf: lower: 9999 (this is positive for this problem) upper: -3.21 0 1 Enter, enter. -0.99933362 1 - .99933362615 = .001 Because the P-value is less than the significance level, reject the null hypothesis. There is sufficient evidence to support the claim that the return rate is less than 20%. If P-value ≤ α reject H0 - If P-value > α fail to reject H0 Assume a significance level of a = 0.01 and use the given information to complete parts (a) and (b) below. Original claim: The mean pulse rate (in beats per minute) of a certain group of adult males is 71 bpm. The hypothesis test results in a P-value of 0.0035. a. State a conclusion about the null hypothesis. (Reject H0 or fail to reject H0.) Choose the correct answer below. A. Reject H0 because the P-value is less than or equal to. B. Reject H0 because the P-value is greater than C. Fail to reject H0 because the P-value is greater than a. D. Fail to reject H0 because the P-value is less than or equal to a. b. Without using technical terms, state a final conclusion that addresses the original claim. Which of the following is the correct conclusion? A. There is sufficient evidence to warrant rejection of the claim that the mean pulse rate (in beats per minute) of the group of adult males is 71 bpm. B. The mean pulse rate (in beats per minute) of the group of adult males is not 71 bpm. C. The mean pulse rate (in beats per minute) of the group of adult males is 71 bpm. D. There is not sufficient evidence to warrant rejection of the claim that the mean pulse rate (in beats per minute) of the group of adult males is 71 bpm. Claim: The mean pulse rate (in beats per minute) of adult males is equal to 69 bpm. For a random sample of 159 adult males, the mean pulse rate is 67.9 bpm and the standard deviation is 11.1 bpm. Find the value of the test statistic. The value of the test statistic is negative -1.25 (Round to two decimal places as needed.) STAT > TESTS > Z-Test > STATS µ: 67.9 σ: 11.1 x: 69 n: 159 ≠ m (make sure this is highlighted) Z = 1.249592093 (round to 1.25) *Note this problem requires all the steps > STAT > TESTS > Z-Test > STATS or (67.9 – 69) / 11.1 √159 √ = square root. |
Home |
Accounting & Finance | Business |
Computer Science | General Studies | Math | Sciences |
Civics Exam |
Everything
Else |
Help & Support |
Join/Cancel |
Contact Us |
Login / Log Out |