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(MAC-1105C) - Final Exam (Proctored)
College Algebra (4
Credit Hours)
I have the steps to solve the problems which should help you with any College Algebra Final Exam. x = dimes x + 3 = quarters 0.10x + 0.25(x + 3) = 3.20 0.10x + 0.25x + 0.75 = 3.20 0.35x + 0.75 = 3.20 0.25x = 2.45 x = 7 = dimes x + 3 = quarters 7 + 3 = quarters The answer is 10. Let’s check the answer. Remember we have 7 dimes and 10 quarters (3 more quarters than dimes). .10(7) + .25(10) = 3.20 .70 + 2.50 = 3.20 3.20 = 3.20 As we look at the answer, we can see that we need to solve a quadratic equation, and not solve for x. So, we will put the equation into quadratic form. Add 32 to both sides of the equation. (3x+5)2 + 32 = 0 Simplify (3x + 5)2 + 32 Rewrite (3x + 5)2 as (3x + 5) (3x + 5) We are left with (3x+5) (3x+5) + 32 = 0 Expand (3x+5) (3x+5) using the FOIL Method 3x(3x) + 3x ⋅ 5 + 5(3x) + 5 ⋅ 5 + 32 = 0 Simplify and combine like terms. 9x2 + 30x + 25 + 32 = 0 Add 25 and 32 9x2 + 30x + 57 = 0 Now, solve the Quadratic Equation like we did earlier. 9x2 + 30x + 57 = 0 ![]() Explanation The easiest way to graph this equation is to pick zero as the starting point.Then we use -3 in the y-intercept form as we are given -3 in the equation, so the first pair we plot would be (0,-3). Solution 2(0) – 3 = -3 Then we can use 1 as the second starting point and evaluate 1 in the equation to find the ordered pair. So, we know the equation is we use 2x – 3 to find the second ordered pair. Solution 2(1) – 3 = -1 Now we can graph the equation. (0,-3) > 2(0) – 3 = -3 (1,-1) > 2(1) – 3 = -1
t = time We would write this equation as so: 48t = 54(t – 2) Simplify 48t = 54t – 108 Subtract 54t from both sides. -6t = -108 Divide both sides by -6. t = 18 Let’s check the answer (please note Car B drove 2 hours less) 48t = 54 x (t – 2) 48(18) = 54 x (18 – 2) 48(18) = 54(16) 864 = 864 College Algebra (MAC-2233) Lessons: Pre-Assessment Exam Final Exam (Proctored) Page 1 2 3 More Lessons 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 |x| + 2 = 10 Subtract 2 from both sides. |x| = 8 Remove the absolute value term from the equation, so this means the answers can be: 8 or -8 Since the multiple-choice answer is -8, the answer is -8. Explanation |x| + 2 = 10Subtract 2 from both sides. |x| = 8 Remove the absolute value term from the equation, so this means the answers can be: 8 or -8 Since the multiple-choice answer is -8, the answer is -8.
Add 13 to both sides. 11x = 44 Divide both sides by 11 x = 4 5x = 2.5 Divide both sides by 5. x = 0.5
The leading coefficient is the leading term, and the degree is 3 because it is the greatest exponent.
-6x = 24 Divide both sides by -6 x = -4 College Algebra (MAC-2233) Lessons: Pre-Assessment Exam Final Exam (Proctored) Page 1 2 3 More Lessons 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 We simply flip the second fraction, multiply, and simplify! So, ![]() ![]() ![]() ![]() ![]() 72 / 12 = 6 Explanation 2/10 + 4/10 = 6/10 Simplify by dividing by 2 = 3/55/6 – 1/6 = 4/6 = Simplify by dividing by 2 = 2/3 2/9 + 4/9 = 6/9 = Simplify by dividing by 3 = 2/3 8/12 – 2/12 = 6/12 = Simplify by dividing by 6 = 1/2
To write ![]() ![]() To write ![]() ![]() ![]() ![]() ![]() ![]() ![]() Now we combine all the terms ![]() ![]() ![]() We are left with ![]() ![]() Now we need another denominator so we what do is We multiple both sides by ![]() ![]() ![]() ![]() ![]() ![]() Now we need to multiply ![]() ![]() We are left with ![]() ![]() Now we have common denominators, so we can combine the top (the bottom keeps 12y as the denominator) ![]() ![]() ![]()
x + 0.2 = 0.7 x + 0.2 – (0.2) = 0.7 + (-0.2) x = 0.7 – 0.2 x = 0.5
x + 12 = -27 x + 12 - (12) = -27 + (-12) x = -27 + -12 = -39 x = -39
5x = 2.5 5x / (5) = 2.5 / (5) 2.5 / 5 = 0.5
2x + 8 = 20 2x + 8 – (8) = 20 – (8) 2x = 12 12 / 2 = 6 Without graphing the equation, we know the value of x = -3 because there are no other values for x with this problem, so we would plug in the value of x and solve for y. y = 4(-3) – 5 y = -12 -5 -12 + -5 = -17 x = -3, y = -17 (-3, -17)
-2y3(-6y3) -2 x -6 = 12 -y3 x -y3 = y6 Now combine. 12y |
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